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12.2 question 3 |
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Answer» Thx Mera bhi dekh lena..bht neend aayi h Sorry ..neend me dekha ..? Here, r= 14cm.. area swept= thetha/360°×πr^2....30/360×22/7×14×14....30/360×44×14....154/3cm^2 Answer will be 154/3 cm^2. Abhinav.. its from exercise 12.3 not 12.2 ◆area of square ABCD - (area of semi circle APD + area of semicircle BPC) ◆14×14 - [1/2 × 22/7(14/2)^2 + 22/7(14/2)^2】 ..solve this then u can get answer.. 42cm^2 |
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