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15cotA=8,find sinA and secA |
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Answer» 15cotA=8Cot A =8/15 = adjacent side/opposite sideTherefore, adjacent side =8 And, opposite side = 15Hypotenuse = ?By phythagoras theorem, (Hypotenuse )^2 = (side)^2 + (side)^2(Hypotenuse)^2 = (8)^2 + (15)^2 (Hypotenuse)^2 = 64 +225(Hypotenuse)^2 = 289(Hypotenuse) = root 289Hypotenuse = 17Therefore, sin A = opp side/ Hypotenuse Sin A = 15/17Sec A = Hypotenuse/ adjacent side Sec A= 17/8Hope it helps you ? SinA=15/17 and secA=17/8 |
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