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1root of the equstion 2x square - 8x - m is5/2 find the other root s the value of m

Answer» {tex}2x^2 - 8x - m = 0{/tex}{tex}\\because{/tex}{tex}\\frac{5}{2}{/tex}\xa0is one root2({tex}\\frac{5}{2}{/tex})2 - 8{tex}\\times{/tex}\xa0{tex}\\frac{5}{2}{/tex}\xa0{tex}- m = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{2 \\times 25}{4}{/tex}\xa0{tex}- 20 - m = 0{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac{25 - 40}{2}{/tex}\xa0{tex}- m = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{-15}{2}{/tex}\xa0= m\xa0{tex}\\Rightarrow{/tex}m =\xa0{tex}\\frac{-15}{2}{/tex}.Also, sum of roots =\xa0-{tex}\\frac{b}{a}{/tex}\xa0=\xa0{tex}\\frac{-(-8)}{2}{/tex}\xa0= 4One root =\xa0{tex}\\frac{5}{2}{/tex}\xa0[given]{tex}\\therefore{/tex}\xa0Other root = 4 -\xa0{tex}\\frac{5}{2}{/tex}\xa0=\xa0{tex}\\frac{3}{2}{/tex}


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