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`2^(0.2)xx64xx8^(1.3)xx4^(0.2)=8^(?)`A. 2.7B. 2.5C. 3.7D. None of these |
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Answer» Correct Answer - D `2^(0.2)xx2^(6)xx(2^(3))^(1.3)xx(2^(2))^(0.2)=(2^(3))^(?)` `rArr (2)^(0.2+6+3.9+0.4)=2^(3?)` `rArr 3?=10.5` `rArr ?=(10.5)/(3)=3.5` |
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