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`7072div(16% "of" 884)=30xx1(1)/(12) "of" (?div39)`A. 60B. 62C. 65D. 55 |
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Answer» Correct Answer - A `7072div((884xx16)/(100))=30xx(13)/(12)xx(?)/(39)` `rArr 7072div 141.44=(5xx?)/(6)` `rArr 50xx6=5xx?` `rArr ?=(50xx6)/(5)=60` |
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