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2 cube each of volume 64 cm3 are joint end to end . find the surface area of the resulting cuboid |
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Answer» Volume of cube = 64cm3 (side)3 =64cm(side)3=(4)3side=4cmLength of cuboid =4+4=8cmBreadth of cuboid =4 cm Height of cubiod =4cm Surface area of cubiod = 2(lb+bh+hl) =2(8×4+4×4+4×8)cm =2(32+16+32)cm =2(80)cm =160cm Ans:• 160 160 160 160 |
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