2 cube each of volume 64cm3 are joined end to end. Find the surface area of the resulting cuboid.

2 cube each of volume 64cm3 are joined end to end. Find the surface ar

1.	2 cube each of volume 64cm3 are joined end to end. Find the surface area of the resulting cuboid.
Answer» Length of cube\xa0=aa3=64⇒a=4Length of cuboid =\xa08=lbreadth of cuboid =\xa04=bheight of cuboid =\xa04=hSurface area\xa0=2(lb+bh+lh)=2((8×4)+(4×4)+(8×4))=2(32+16+32)=160\xa0cm2 Given,Volume of each cube = 64cm^3length of the cuboid =4+4= 8cmBreadth of the cuboid =4 cmHeight of the cuboid = 4 cmT.S.A of cuboid =2(lb+bh+hl)=2(8×4+4×4+4×8)=2(32+16+32)=2(80)