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2/xsquare_5/x+2=0 |
| Answer» {tex}{2\\over x^2} - {5\\over x} +2 =0 \\\\{/tex}Multiply by x2\xa0both side we get\xa0{tex}2 - 5x + 2x^2 = 0 \\\\2x^2 - 5x +2 = 0 \\\\2x^2-4x-x+2 = 0 \\\\2x(x-2)-1(x-2) = 0 \\\\(2x-1)(x-2) = 0 \\\\{/tex}{tex}x = {1\\over 2}, 2 {/tex} | |