1.

20 L of a mixture contains alcohol and water in the ratio 2 : 3. If 4 L of water is mixed in it, the percentage of alcohol in the new mixture will be1). 502). 253). 204). 33.33%

Answer»

Amount of ALCOHOL in the mixture = 2/5 × 20 = 8 L

And amount of water in the mixture = 20 – 8 = 12 L

Given, 4 L of water is added. HENCE,

Amount of water in the new mixture = 16 L

Hence, the percentage of alcohol in the new mixture = $(\frac{8}{{24}} \TIMES 100 = 33\frac{1}{3}\%)$



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