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`((243)^(n/5).3^(2n+1))/(9^(n).3^(n-1))` का मान क्या है?A. 1B. 9C. 3D. `3^(n)` |
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Answer» Correct Answer - B `((243)^(n/5).3^(2n+1))/(9^(n).3^(n-1))=((3^(5))^(n/5).3^(2n+1))/(3^(2n).3^(n-1))` `=(3^(n+2n+1))/(3^(2n+n-1))=(3^(3n+1))/(3^(3n-1))=3^(3n+1-1-3n+1)` `3^(2)=9` |
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