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Find the value of k for which the roots are real and equal in the following equation:Kx2 – 2√5x + 4 = 0 1. 5/42. √53. 2√34. 4/5 |
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Answer» Correct Answer - Option 1 : 5/4 Given: Kx2 – 2√5x + 4 = 0 Concept used: If the roots of the equation ax2 + bx + c = 0 are real and equal, Then b2 – 4ac = 0 Calculation: Kx2 – 2√5x + 4 = 0 If roots are real and equal, then b2 – 4ac = 0 ⇒ (-2√5)2 – 4 × k × 4 = 0 ⇒ 20 – 16k = 0 ⇒ 16k = 20 ⇒ k = 5/4 ∴ The value of k is 5/4. |
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