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[ 28.If f(x)=|[0,x-a,x-bx+a,0,x-cx+b,x+c,0]| then,[ 1) f(a)=0, 2) f(b)=0]]A. `f(a)=0`B. `f(b)=0`C. `f(0)=0`D. `f(1)=0` |
Answer» Correct Answer - C We have `f(x)=|(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0)|` `implies f(a)=|(0,0,a-b),(2a,0,a-c),(a+b,a+c,0)|` `=[(a-b)}2a.(a+c)}]!=0` `:. f(b)=|(0,b-a,0),(b+a,0,b-c),(2b,b+c,0)|` `=-(b-a)[2b(b-c)]` `=-2b(b-a)(b-c)!=0` `:.f(0)=|(0,-a,-b),(a,0,-c),(b,c,0)|` `=a(bc)-b(ac)` `=abc-abc=0` |
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