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| 1. |
2cos^2θ-1÷sinθcosθ=cotθ-tanθ |
| Answer» LHS - 2cos^2theta - (cos^2 theta + sin^2 theta) / sintheta × cos theta => cos^2 theta - sin^2 theta / sin theta × cos theta => [cos^2 theta/sin theta × cos theta ] - [sin^2 theta/ sin theta × cos theta ] => (cos theta / sin theta) - (sin theta / cos theta) => cot theta - tan theta... | |