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2x^2+2x-424=0 middle factorise |
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Answer» Answer :•2x^2+2x-424=0•x^2+x-212=0 (dividing the equation by 2 in each terms) a=1,b=1and c=-212•D=b^2-4ac=(1)^2-4(-212)*1=1- 848=-847•x=-b+rootD/2a=-1+root-847/2=-1+847i/2And,x=b+rootD/2a=1+root-847/2=1+847i/2 Hence, x=-1+847i/2,x=1+847i/2 Join Betternation.xyz This is a site where u can have a lot of friends and fun ? ? |
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