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| 1. |
2x+3y=5,3x+2y=10 then x_y=? |
| Answer» 2x+3y=5.......(1)3x+2y=10.......(2)Substracting 1 from 23x+2y-(2x+3y)=10-53x+2y-2x-3y=53(x-y)-2(x-y)=5(x-y)(3-2)=5X-Y=5 | |