InterviewSolution
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InterviewSolution
| 1. |
2x2+3X+1=0 |
| Answer» Given\xa02x2+3x+1=0On comparing this equation with\xa0ax2\xa0+ bx + c = 0, where\xa0a = 2, b = 3, c = 1∴\xa0b2\xa0− 4ac = (5)2\xa0− 4 × 2 × 1= 9 − 8= 1x = −b±b2−4ac\u200b\u200b / 2a= −3±1\u200b\u200b /\xa02×2x = −3+1 / 4\u200b\xa0or\xa0x = −3−1\u200b / 4x = −2 / 4\u200b\xa0or\xa0x = −4\u200b / 4x = −1/2\u200b\xa0or\xa0x = −1 | |