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✓2x2+7x+5√2=0 |
| Answer» We have,\xa0{tex}\\sqrt2x^2 +7x +5\\sqrt2 =0{/tex}{tex}\\implies \\sqrt2x^2 +2x +5x+5\\sqrt2 =0{/tex}{tex}\\implies \\sqrt2x (x +\\sqrt2) + 5 (x + \\sqrt2) = 0{/tex}{tex}\\implies (\\sqrt2x+5) (x+\\sqrt2) =0{/tex}{tex}Either\\, \\sqrt2x+5 =0\\, or \\,x+\\sqrt2 =0{/tex}{tex}\\implies x = {-5 \\over \\sqrt2},\\, -\\sqrt2{/tex}{tex}\\therefore x = {-5 \\over \\sqrt2},\\, -\\sqrt2{/tex}\xa0are the required roots. | |