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√2x2 + 7x + 5√2=0 |
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Answer» No answer √2 x² +7x +5\xa0√2 = 0⇒\xa0√2 x² + 5x + 2x + 5√2 = 0\ufeff\ufeff⇒\xa0√2x² + 5x +\xa0√2*√2*x + 5√2=0⇒ x(√2x\xa0+\xa05) +\xa0√2(√2x\xa0+ 5) =0⇒ (x+√2)(√2x+5)\xa0=\xa00That gives x=\xa0-\xa0√2 or x= -\xa05/√2 |
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