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2y-x=8,5y-x =14,-x+y/2=1/2 are vertices of triangle. Determine graphically the vertices of triangle |
| Answer» {tex}2y - x = 8{/tex}{tex}5y - x = 14{/tex}{tex}y - 2x = 1{/tex}Now, {tex}2y - x = 8{/tex}{tex}x = 2y - 8{/tex}When {tex}y = 2{/tex} then {tex}x = - 4{/tex}When {tex}y = 5{/tex} then {tex}x = 2{/tex}Thus, we have the following table giving points on the line {tex}2y - x = 8{/tex}\tx-42y25\tNow, {tex}5y - x = 14{/tex}{tex}x = 5y - 14{/tex}When {tex}y = 2{/tex}, then {tex}x = 1{/tex}When {tex}y = 3{/tex} , then {tex}x = 1{/tex}Thus, we have the following table giving points on the line {tex}5y - x = 14{/tex}\tx-41y23\tWe have,{tex}y - 2x = 1{/tex}{tex}x = \\frac{{y - 1}}{2}{/tex}When {tex}y = -1{/tex}, then {tex}x = 1{/tex}When\xa0{tex} y = 3{/tex} , then {tex}x = 1{/tex}Thus, we have the following table giving points on the line {tex}y - 2x = 1{/tex}\tx-11y-13\tFrom the graph of the lines represent by the given equation, we observe that the lines taken in pairs intersect at points A(-4, 2) B(1, 3) and C(2, 5).Hence the vertices of the triangle are A(-4, 2) B(1, 3) and C(2, 5) | |