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| 1. |
√3+√5 prove it is a irrational number. |
| Answer» Let √3+√5 be a rational number.A rational number can be written in the form of p/q where p,q are integers.√3+√5 = p/q√3 = p/q-√5Squaring on both sides,(√3)² = (p/q-√5)²3 = p²/q²+√5²-2(p/q)(√5)√5×2p/q = p²/q²+5-3√5 = (p²+2q²)/q² × q/2p√5 = (p²+2q²)/2pqp,q are integers then (p²+2q²)/2pq is a rational number.Then √5 is also a rational number.But this contradicts the fact that √5 is an irrational number.So,our supposition is false.Therefore, √3+√5 is an irrational number. | |