3 digit no which is divisible by 9 how many term in this ap

1.	3 digit no which is divisible by 9 how many term in this ap
Answer» 108 is smallest and 999 is largest three digit number which is divisible by 9 ,so AP is108,117,...….....,999a=108, d=9, a\u200b\u200b\u200b\u200b\u200b\u200bn=999a\u200b\u200b\u200b\u200b\u200b\u200bn=a+(n-1)d999=108+(n-1)9 9( n-1 )=999-108n-1=891/9n-1=99n =99+1n=100There are \'100 \' terms

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