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36x²+12ax+(a²-b²)=0 solved by factorisation method |
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Answer» 36x²-12ax+(a²-b²)=0 First factorize => (a^2-b^2)= (a+b)(a-b)Now,36x^2+12ax+(a+b)(a-b)=036x^2+6(a+b)x+6(a-b)x+(a+b)(a-b)=06x(6x+a+b)+(a-b)(6x+a+b)=0(6x+a+b)(6x+a-b)=0Therefore,6x+a+b=0 and 6x+a-b=0Hence,x=-(a+b)/6 andx=(b-a)/6 |
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