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| 1. |
3x^2- 2root6x +2=0 |
| Answer» 3 x^{2} -2√6x+2=03 x^{2} -√6x-√6x+2=0√3 x^{2} *√3 x^{2} -√3x*√2x-√3x*√2x+√2*√2=0√3x(√3x-√2)-√2(√3x-√2)=0(√3x-√2)(√3x-√2)=0x=√2/√3Therefore the equation has two equal roots √2/√3 | |