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3x+4y=10 and 2x-2y=2 solve by elimination method |
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Answer» Step 1: Multiply eq. 1 by 2 and eq. 2 by 3 {to equalise coefficient of x} 6x+8y=20 (eq. 3) 6x-6y= 6. ( eq.4)Step 2: Subtract eq.4 from eq. 3 6x+8y=20 6x-6y=6 -. +. - -------------------- 14y = 14 y=1Step 3:Find x by substitution method x= 6+6y/6. =. 1 + y. =. 1+1 x =2 3x+4y=10 (i)2x-2y=2 (ii)Multiply eqn (i) by\xa02 and eqn (ii) by 3\xa0We get,6x+8y=20 - (iii)6x-6y=6 - (iv)Now solving eqn(iii) and (iv) we get 14y = 14 i.e\xa0y=1Substituting y=1 in eqn (i) we get 3x=6 i. e. x=2\xa0 |
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