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| 1. |
3x- 4y+22=0 and 4x-3y+13 by substitution |
| Answer» 3x-4y+22=0....eq(1)4x-3y+13=0.....eq(2)From eq(1)x=(-22+4y)/3...eq(3)By putting value of x in eq(2),we get4x-3y+13=04(-22+4y/3)-3y+13=0(-88+16y-9y+39)/3=0-49+7y=07y=49y=7Putting value of y in eq(3),we getx=(-22+4*7)/3x=(-22+28)/3x=2Hence,x=2 and y=7 | |