3x-5y-4=0 and 9x=2y+7

1.	3x-5y-4=0 and 9x=2y+7
Answer» 3x-5y=4---------(1)9x-2y=7---------(2)from Equation (2) we get,9x-2y=7 9x=7+2yx=7+2y/9putting the value of x in equation (1)3x-5y=43×(7+2y/9)-5y=47+2y/3-5y=4 7+2y-15y =4________ 3 7-13y=. 4/1______ 3cross multiplication7-13y=12-13y=12-7-13y=513y =-5y=-5/13putting the value of y in eqution (3)x =7+2y/9x=[7+2×(-5/13)]×1/9x=[7-10/13]×1/9x=[91-10/13] ×1/9x=81/13×1/9x=9/13hence x=9/13and y-5/13 3X - 5Y = 4----------(1)9X - 2Y = 7-------------(2)From EQUATION (1) we get,3X - 5Y = 43X = 4+5YX = 4+5Y/3 -------------(3)Putting the value of X in equation (2)9X - 2Y = 79 × (4+5Y/3) - 2Y = 73(4+5Y) - 2Y = 712 + 15Y - 2Y = 713Y = 7 -1213Y = -5Y = -5/13Putting the value of X in equation (3)X = 4+5Y/3 => 3 + 5 × -5/13 = 3 - 25/13 /3X = 39 - 25/13/3 = 14/13/3 => 14/13 × 1/3 => 14/9\xa0 y=5/17 and x=43/51

Discussion