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| 1. |
3x-y+7/11+2=102y+x+11/7=10 |
| Answer» Given,\xa0{tex}3x -{/tex}{tex}\\frac{y+7}{11}{/tex}\xa0{tex}+ 2 = 10{/tex}{tex}\\Rightarrow \\frac{33 x-(y+7)+22}{11}=10{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}33x - y - 7 + 22 = 110{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}33x - y = 95{/tex} ..(i)Also,\xa0{tex}2 y+\\frac{x+11}{7}{/tex}\xa0= 10{tex}\\Rightarrow \\quad \\frac{14 y+x+11}{7}{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}14y + x + 11 = 70{/tex}{tex}14y + x = 59{/tex}{tex}14y = 59 - x{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0y =\xa0{tex}\\frac{59-x}{14}{/tex}eq. (i) becomes33x -\xa0{tex}\\left(\\frac{59-x}{14}\\right){/tex}\xa0= 95{tex}\\Rightarrow \\quad \\frac{462 x-59+x}{14}{/tex}\xa0= 95{tex}\\Rightarrow{/tex}\xa0463x - 59 = 1330{tex}\\Rightarrow{/tex}\xa0x = 3When x = 3 eq. (i) becomes33(3) - y = 95{tex}\\Rightarrow{/tex}\xa0y =4 | |