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InterviewSolution
| 1. |
3x2-4√3x+4=0 find roots |
| Answer» The given quadratic equation is{tex}3 x ^ { 2 } - 4 \\sqrt { 3 } x + 4 = 0{/tex}Here, a = 3, {tex}b = - 4 \\sqrt { 3 }{/tex}, c = 4{tex}\\therefore{/tex} discriminant = b2 - 4ac{tex}= ( - 4 \\sqrt { 3 } ) ^ { 2 } - 4 ( 3 ) ( 4 ){/tex}= 48 - 48 = 0Hence, the given quadratic equationhas two equal real roots.The roots are {tex}= - \\frac { b } { 2 a } , - \\frac { b } { 2 a }{/tex}{tex}\\text { i.e. } - \\frac { ( - 4 \\sqrt { 3 } ) } { 2 \\times 3 } , - \\frac { ( - 4 \\sqrt { 3 } ) } { 2 \\times 3 } , \\text { i.e. } \\frac { 2 } { \\sqrt { 3 } } , \\frac { 2 } { \\sqrt { 3 } }{/tex} | |