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| 1. |
4(sec²69*-cot²21*)=2/3,find tan90*+3tan²64*/cot²26*=x/3 |
| Answer» {tex}4\\left(\\frac{\\sec ^{2} 59^{\\circ}-\\cot ^{2} 31^{\\circ}}{3}\\right)-\\frac{2}{3} {/tex}{tex}sin 90° + 3 tan^2\xa056° tan^2\xa034°\xa0{/tex}{tex}=\\frac{x}{3}{/tex}{tex}\\Rightarrow 4\\left(\\frac{\\sec ^{2} 59^{\\circ}-\\tan ^{2} 59^{\\circ}}{3}\\right)-\\frac{2}{3}{/tex}{tex}\\times{/tex}\xa0{tex}1 + 3 tan^2\xa056° cot^2\xa0(90° - 34°){/tex}\xa0{tex}=\\frac{x}{3}{/tex}{tex}\\Rightarrow 4\\left(\\frac{\\sec ^{2} 59^{\\circ}-\\tan ^{2} 59^{\\circ}}{3}\\right)-\\frac{2}{3}{/tex}\xa0+ 3 tan2\xa056° cot2\xa056°{tex}=\\frac{x}{3}{/tex}{tex}\\Rightarrow 4 \\times \\frac{1}{3}-\\frac{2}{3}+3 \\times 1=\\frac{x}{3}{/tex}{tex}\\Rightarrow \\frac{4}{3}-\\frac{2}{3}+3=\\frac{x}{3}{/tex}{tex}\\Rightarrow{/tex}\xa0x = 11 | |