4sin theta =3 cos theta find the value of 12 sin theta -7 cos theta/8 sin theta +3 cos theta

4sin theta =3 cos theta find the value of 12 sin theta -7 cos theta/8

1.	4sin theta =3 cos theta find the value of 12 sin theta -7 cos theta/8 sin theta +3 cos theta
Answer» Given :\xa0{tex}4 sin \\theta = 3 cos \\theta {/tex}=>\xa0{tex}{sin\\theta\\over cos\\theta }= {3\\over 4}{/tex}=>\xa0{tex}tan \\theta = {3\\over 4}{/tex}To find :\xa0{tex}{12sin\\theta - 7cos \\theta\\over 8 sin \\theta+ 3 cos\\theta}{/tex}Divide numerator and denominator by\xa0{tex}cos \\theta {/tex}, we get{tex}12 tan\\theta - 7\\over 8 tan \\theta + 3{/tex}=\xa0{tex}{9-7\\over 6+3}={ 2\\over 9}{/tex}