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4u^2+8u

Answer» 4usquare + 8u =4u(u+2)U=0 and also u =-2So the zeroes are o and -2 Case 1... (a+b)=0+(-2) = -(-8)/4 =(-b/a)-2 = 8/4Case 2... (a*b) = (0)(-2) = 0/4= (c/a)0=0/4 Hence verified...Hope sooo ...it would help u..?


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