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4usqare plus 8u , Find the zeroes and verify the relationship between the zeroes and the cofficients

Answer» 4u²-8u=0=4u(u-2)=0=4u=0=u=0u-2=0u= 2Let us consider 2 as alpha and 0as betaAlpha+beta=-b/a=2+0= 8/4=2=2Alpha ×beta = c/a=2×0=0/4=0=0Hence relationship has verified
As it is given.. 4usquare+8u=0Then.... Take 4 nd u as common,4u(u+2)Equating 4u nd u+2 equal to 0,4u=0.....u=0u+2=0....u=-2Then.....sum of zeroes=-b/a ......0+(-2)=-8/4 -2. = -2Then.... product of zeroes=c/a ..... ............0*(-2) =0/4 0. = 0
Yaar , 4u Ko common Lelo toh (u+2) bachega, fir 4u=0 then u=0, and u+2=0 then u=-2


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