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| 1. |
4x +6/y=156x-8/y=15 |
| Answer» The given equations are4x +\xa0{tex}\\frac{6}{y}{/tex}\xa0= 15 .......... (i)6x -\xa0{tex}\\frac{8}{y}{/tex}\xa0= 14 ......... (ii)Multiply (i) by 3 and (ii) by 2 , we get12x +\xa0{tex}\\frac{18}{y}{/tex}\xa0= 45 ............(iii)12x -\xa0{tex}\\frac{16}{y}{/tex}\xa0= 28 ............(iv)Subtracting (iii) and (iv), we get{tex}\\Rightarrow{/tex}\xa02 = yPut y = 2 in (i) , we get4x +\xa0{tex}\\frac{6}{2}{/tex}\xa0= 15{tex}\\Rightarrow{/tex}4x = 15 -3{tex}\\Rightarrow{/tex} 4x =12\xa0{tex}\\Rightarrow{/tex}\xa0x =\xa0{tex}\\frac{12}{4}{/tex} = 3Hence x = 3 and y = 2 is the solution of given system of equations. | |