1.

5,(2k-3),9 is an a.p ,find the value of k

Answer» 5
Indirectly mera answer right he
sorry by mistake used 2k - 9 in place of 2k - 3.So, solve same by same method.
5, (2k -9), 9 is an apd = (2k -9) - 5 = 2k-9 - 5 = 2k - 14 .... (i)also d = 9 - (2k-9) = 9 - 2k - 9 = - 2k ...... (ii)From (i) and (ii)2k - 14 = -2k2k + 2k = 144k = 14k = 14/4 = 7/2
K=5


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