-5 is one the zeroes of 2x^2 +px -15, zeroes of p(x^2+x)+k are equal to each other. Find value of k

-5 is one the zeroes of 2x^2 +px -15, zeroes of p(x^2+x)+k are equal t

1.	-5 is one the zeroes of 2x^2 +px -15, zeroes of p(x^2+x)+k are equal to each other. Find value of k
Answer» P(x)= 2x^2+px-15Zero is given -5P(-5)=0Than 2(-5)^2+p(-5)-15=0 50-5p-15=035=5p7=pPut value of p in p(x^2+x)+k 7x^2+7x+kBy using b^2-4ac=049-28k=0K=-49/-28=7/4Thanks