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5x-4y+8=07x+6y-8=0

Answer» 5 x - 4 y - 8 = 07 x + 6 y - 9 = 0Here, a1= 5, b1\xa0= -4, c1= 8a2= 7, b2= 6, c2\xa0= 9We see that\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } \\neq \\frac { b _ { 1 } } { b _ { 2 } }{/tex}Hence, the lines representing the given pair of linear equations intersect at the point and the equations are consistent having unique solution.


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