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5x²+8x-4=0

Answer» 5x²+8x-4=05x²+(10-2)x-4=05x²+10x-2x-4=05x(x+2)-2(x+2)=0(5x-2)(x+2)=0So, (x=⅖) & [x=(-2)]
5x²+8x-45x²+(10-2)x-45x²+10x-2x-45x(x+2)-2(x+2)(x+2),(5x-2)x=-2,x=2/5
5x2 + 8x - 4 = 05x2 + 10x - 2x - 4 =0 5x(x+2) -2(x+2) = 0(5x-2) (x+2) = 0X = -2, 2/5


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