6x2-√2x-2=0 find the two roots by prime factorization method

1.	6x2-√2x-2=0 find the two roots by prime factorization method
Answer» 6x2\xa0- √2 x - 2 = 06x2 - 3 √2 x- 2\xa0√2 x-2=03\xa0√2x(\xa0√2x-1) - 2(\xa0√2x-1)=0(\xa0√2x-1)(3\xa0√2x-2)=0hence x=\xa0√2/3 and x= 1/ 6x2 - 3under root 2 x- 2under root 2x -2 now factors come 6x2 -

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