1.

7sin^2A+3cos^2A=4.S.T: tanA=1/√3

Answer» 4sinAsq+3sinAsq+3cosAsq=43(sinAsq +cosAsq)+4sinAsq=43+4sinAsq=44sinAsq=1SinAsq=1/4SinA=√1/4=1/2SinA=30TanA=30TanA=1/√3


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