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| 1. |
7sin^2A+3cos^2A=4 show that tanA=1/root3 |
| Answer» {tex}7sin^2A+3cos^2A=4{/tex}{tex}=> 4sin^2A+ 3sin^2A+3cos^2A=4{/tex}{tex}=> 4sin^2A+ 3(sin^2A+cos^2A)=4{/tex}{tex}=> 4sin^2A+ 3=4{/tex}{tex}=> 4sin^2A = 1 {/tex}{tex}=> sin^2A = {1\\over 4} {/tex}{tex}=> sinA = {1\\over 2}{/tex}{tex}=> sinA = sin 30^o{/tex}{tex}=> A = 30^o{/tex}So\xa0{tex}tan A= tan 30^o = {1\\over \\sqrt 3}{/tex} | |