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7sin2A+3cos2A=4Show thatTanA=1/√3(sin2 means sin square and cos2 means cos square) |
| Answer» 7sin2A + 3cos2A = 4= 7sin2A = 4- 3cos2A= 7sin2A = 4 - 3( 1 - sin2A )= 7sin2A =4 - 3 + 3sin2A= 7sin2A - 3sin2A = 1= 4sin2A = 1=sinA=1/2=p/hBy pythagoras theorembase= root3Put the value for tanA i.e. p/bAnd u have ur answer | |