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| 1. |
9x-3kx+k=0 find the value of k quadratic equation |
| Answer» a = 9, b = - 3 k, c = kSince roots of the equation are equalSo,\xa0{tex}b ^ { 2 } - 4 a c = 0{/tex}{tex}( - 3 k ) ^ { 2 } - ( 4 \\times 9 \\times k ) = 0{/tex}{tex}9 k ^ { 2 } - 36 k = 0{/tex}{tex}k ^ { 2 } - 4 k = 0{/tex}k (k -4 ) = 0k = 0 or k = 4\xa0 | |