InterviewSolution
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InterviewSolution
| 1. |
9x^-3x-2=0 |
| Answer» We have,9x2 - 3x - 2 = 0{tex}\\Rightarrow{/tex}\xa09x2 - 6x + 3x - 2 = 0{tex}\\Rightarrow{/tex}\xa03x(3x - 2) + 1(3x - 2) = 0{tex}\\Rightarrow{/tex}\xa0(3x - 2)(3x + 1) = 0{tex}\\Rightarrow{/tex}\xa03x - 2 = 0 or, 3x + 1 = 0\xa0{tex}\\Rightarrow \\quad x = \\frac { 2 } { 3 } \\text { or, } x = - \\frac { 1 } { 3 }{/tex}Thus,\xa0{tex}x = \\frac { 2 } { 3 } \\text { and } x = - \\frac { 1 } { 3 }{/tex} are the required roots of the given equation. | |