1.

`|[(a+1)(a+2), a+2, 1], [(a+2)(a+3), a+3, 1], [(a+3)(a+4), a+4, 1]| =-2`

Answer» `Delta = |[a^(2) + 3a+2, a+2, 1], [a^(2) +5a +6, a+3, 1], [a^(2) +7a +12, a+4, 1]|`
Now, apply `R_(2) to R_(2) -R_(1) "and"R_(3) to R_(3) -R_(1)`


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