InterviewSolution
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InterviewSolution
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A 4 ohm resistence wire is doubled on it then calculate the new resistence |
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Answer» 4×2=8 Hence the new resistence is 8ohm Let the original length of wire be -l And area of cross section be -A Since given resistance -4ohm We know R=pl/A. (1)(we know v=Al therefore A=V/l) (2) Now substituting (2) in (1) R=pl/V/l Therefore R=pl*2(l square) /V (3) Let new resistance be R\' And new length = 2l So R\'= p2l/A. (4) Substituting (2) in (4) R\'=p(2l)*2 (2l square) /vR\'=p4l*2/vR\'=4pl*2/v Therefore R\'=4RR\'=16ohm |
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