1.

A 450 ml mixture of two liquids contains 30% liquid A and the rest is liquid B. How much liquid B must be added so that the mixture contains 80% liquid B?1). 150 ml2). 225 ml3). 240 ml4). 330 ml

Answer»

Quantity of liquid B = 70% of 450 = 315 ML

Let x ml of liquid B be added.

315 + x = 80% of (450 + x)

⇒ 315 + x = 0.8 × (450 + x)

⇒ 315 + x = 360 + 0.8x

⇒ 0.2x = 45

⇒ x = 225


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