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a=5,d=3,an=50 find n and Sn.

Answer» Given,\xa0a=5,d=3,an\u200b=50⇒a+(n−1)d=50⇒5+(n−1)3=50⇒5+3n−3=50⇒3n=48⇒n=16∴S16\u200b=216\u200b[2a+(16−1)d]=8[2×5+15×3]=440Hence,\xa0n=16,S16\u200b=440


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