InterviewSolution
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InterviewSolution
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`=|a a^2 0 1 2a+b(a+b)0 1 2a+3b|`is divisible by`a+b`b. `a+2b`c. `2a+3b`d. `a^2`A. `a+b `B. `a+2b`C. `2a+3b`D. `a^(2)` |
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Answer» Correct Answer - A::B `Delta = |{:(a,,a^(2),,0),(1,,2a+b,,(a+b)),(0,,1,,2a+2b):}|` `=a |{:(1,,a,,0),(1,,(2a+b),,(a+b)),(0,,1,,2a+3b):}|` `=a(a+b) |{:(1,,a,,0),(0,,1,,(a+b)),(0,,1,,2a+3b):}|" "(R_(2) to R_(2) -R_(1))` `=a(a+b) (2a+3b-a-b)` `=a(a+b) (a+2b)` |
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