1.

A and B are two alloys of tin and lead prepared by mixing metals in the ratios 3 : 5 and 6 : 11 respectively. Equal quantities of these alloys are melted to form a third alloy C. The ratio of tin and lead in the alloy C is1). 95 : 1742). 42 : 913). 99 : 1734). 24 : 20

Answer»

From the given DATA,

Tin present in 1 GM of A = 3/8 gm

Tin present in 1 gm of B = 6/17 gm

Tin present in 2 gm of C = 3/8 + 6/17 = 99/136 gm

Lead present in 1 gm of A = 5/8 gm

Lead present in 1 gm of B = 11/17 gm

Lead present in 2 gm of C = 5/8 + 11/17 = 173/136 gm

⇒ Ratio of tin and Lead in C = (99/136) : (173/136) = 99 : 173


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