1.

`|[a-b, b-c, c-a], [b-c, c-a, a-b], [c-a, a-b, b-c]|=?`A. (a+b+c)B. 3(a+b+c)C. 3abcD. 0

Answer» Correct Answer - D
`R_(1) to (R_(1) + R_(2) + R_(3))` gives all zeros in `R_(1) "and hence"Delta = 0`


Discussion

No Comment Found